54 lines
1.5 KiB
Plaintext
54 lines
1.5 KiB
Plaintext
#Newsgroups: comp.unix.admin,comp.unix.solaris,comp.unix.shell
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#From: gwc@root.co.uk (Geoff Clare)
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#Subject: Re: timeout -t <sec> <unix command> (Re: How to give rsh a shorter timeout?)
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#Message-ID: <EoBxrs.223@root.co.uk>
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#Date: Fri, 13 Feb 1998 18:23:52 GMT
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#
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# Conversion to bash v2 syntax done by Chet Ramey <chet@po.cwru.edu
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# UNTESTED
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#
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prog=${0##*/}
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usage="usage: $prog [-signal] [timeout] [:interval] [+delay] [--] <command>"
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SIG=-TERM # default signal sent to the process when the timer expires
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timeout=60 # default timeout
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interval=15 # default interval between checks if the process is still alive
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delay=2 # default delay between posting the given signal and
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# destroying the process (kill -KILL)
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while :
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do
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case $1 in
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--) shift; break ;;
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-*) SIG=$1 ;;
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[0-9]*) timeout=$1 ;;
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:*) EXPR='..\(.*\)' ; interval=`expr x"$1" : "$EXPR"` ;;
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+*) EXPR='..\(.*\)' ; delay=`expr x"$1" : "$EXPR"` ;;
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*) break ;;
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esac
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shift
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done
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case $# in
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0) echo "$prog: $usage" >&2 ; exit 2 ;;
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esac
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(
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for t in $timeout $delay
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do
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while (( $t > $interval ))
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do
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sleep $interval
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kill -0 $$ || exit
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t=$(( $t - $interval ))
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done
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sleep $t
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kill $SIG $$ && kill -0 $$ || exit
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SIG=-KILL
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done
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) 2> /dev/null &
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exec "$@"
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